Bài tập mạch điện 3 pha mắc hình sao năm 2024
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0% found this document useful (0 votes) 54 views 24 pages Original TitleCHƯƠNG-4-MẠCH-ĐIỆN-3-PHA Copyright© © All Rights Reserved Available FormatsPDF, TXT or read online from Scribd Share this documentDid you find this document useful?Is this content inappropriate?0% found this document useful (0 votes) 54 views24 pages CHƯƠNG 4 MẠCH ĐIỆN 3 PHAUploaded byDương Trần Khánh Jump to Page You are on page 1of 24 Search inside document Reward Your CuriosityEverything you want to read. Anytime. Anywhere. Any device. No Commitment. Cancel anytime. Uploaded byHồ Thanh Thiên 0% found this document useful (0 votes) 2K views 18 pages Original TitleChuong 3_Mach 3 pha Copyright© © All Rights Reserved Available FormatsPDF, TXT or read online from Scribd Share this documentDid you find this document useful?Is this content inappropriate?0% found this document useful (0 votes) 2K views18 pages Chuong 3 - Mach 3 PhaUploaded byHồ Thanh Thiên Jump to Page You are on page 1of 18 Search inside document Reward Your CuriosityEverything you want to read. Anytime. Anywhere. Any device. No Commitment. Cancel anytime. Ví dụ 1: Cho mạch điện ba pha đối xứng như Hình 2. Biết 𝐸𝐴\=200∠0𝑜[𝑉]. Tải 1 nối hình sao (Y) có: 𝑍1\=12+𝑗9[𝛺] Tải 2 nối hình tam giác (∆) có: 𝑃2\=6(𝐾𝑊); 𝑐𝑜𝑠𝜑2\=0,84 (𝞿𝟐\>𝟎).
LỜI GIẢI
❖ Xét tải 1 nối sao: 𝑼𝒅𝟏\=√𝟑.𝑼𝒑𝟏\=𝑼𝒅\=√𝟑.𝑬𝒑\=𝟐𝟎𝟎√𝟑(𝑽) Id1\=Ip1 \=Up1 Z1\=Ep Z1\=200 √(122+92)\=13,33(A) ❖ Xét tải 2 nối tam giác: 𝑼𝒅𝟐\=𝑼𝒑𝟐\=𝑼𝒅\=√𝟑.𝑬𝒑\=𝟐𝟎𝟎√𝟑(𝑽) Id2\=P2 √3.Ud2.cosφ2\=6000 √3.200√3.0,84\=11,9(A) \=>Ip2\=Id2 √3\=11,9 √3\=6,87(A) 𝐶𝑜𝑠𝜑2\=0,84\=>𝜑2\=32,860 (𝐷𝑜𝜑2\>0)
𝑃𝑡𝑚 \=𝑃1+𝑃2\=3𝑅1𝐼𝑝1 2+𝑃2\=3.13,332.12+6000\=12396,8(𝑊) 𝑄𝑡𝑚\=𝑄1+𝑄2\=3𝑋1𝐼𝑝1 2+𝑃2.𝑡𝑔𝜑2\=3.13,332.9+6000.𝑡𝑔(32,860)\=8673,23(𝑉𝐴𝑟) 𝑆𝑡𝑚\=√(𝑃𝑡𝑚 2+𝑄𝑡𝑚 2\=15129,62(𝑉𝐴)
+ Tính dòng điện dây tổng: 𝑰𝒅\=𝑺𝒕𝒎 √𝟑.𝑼𝒅\=𝟏𝟓𝟏𝟐𝟗,𝟔𝟐 √𝟑.𝟐𝟎𝟎.√𝟑\=𝟐𝟓,𝟐𝟏(𝑨) + Hệ số công suất cosφ 𝒄𝒐𝒔𝝋𝒕𝒎\=𝑷𝒕𝒎 𝑺𝒕𝒎 \=𝟏𝟐𝟑𝟗𝟔,𝟖 𝟏𝟓𝟏𝟐𝟗,𝟔𝟑\=𝟎,𝟖𝟐 Z2 Z2 Z1Z1Z1 A1 B1 C1 A2 B2 C2 EB . Id .Id2 . Id1 . Z2 EC . EA . Hình 2 Why is this page out of focus?This is a Premium document. Become Premium to read the whole document. Why is this page out of focus?This is a Premium document. Become Premium to read the whole document. |
