What is the compound interest for rupees 12000?

Solution : We know that amount A at the end of n years at the rate of r% per annum when the interest is compounded annually is given by
` A = P (1+r/100)^(n)`
Here, ` P = Rs. 12000, r = 12, and n = 10` .
` :. A = Rs.[12000(1+12/100)^(10)]`
` = Rs. [ 12000(1+3/25)^(10)]`
` = Rs. [ 12000((25+3)/25)^(10)]`
` = Rs.[12000(28/25)^(10)]`
Now, ` A = Rs. 12000(28/25)^(10)`
` rArr log A = log 12000+10(log 28- log 25)`
` = 4.0792+10 (1.4472-1.3979)`
` = 4.0792+0.493=4.5722`
` rArr A =" antilog "(4.5722) = 37350`.
So, the amount after 10 years is Rs. 37350.
Hence, Compound interest = Rs. (37350 - 12000) = Rs. 25350.

What is the compound interest of 12000?

Hence, the compound interest is Rs. 2,520.

What is the compound interest in Rs on a sum of Rs 12000 for 2 years at the rate of 5% per annum compounded annually?

∴ Compound Interest is Rs. 1230.

What is the compound interest accrued on an amount of Rs 12000 /

Now Compound interest = A - P ⇒ Compound interest = Rs. 15972 - Rs. 12000 = Rs. 3972.

What is the compound interest on Rs 15000 /

15000 at 5% per annum for two years is Rs 1500 and the amount after 2 years is Rs. 16500.