How many 3-digit numbers can be formed from the digits 1, 2, 3, 4,5 if the digits cannot be repeated
|
Table of Contents Show
Total Number of Numbers which can be formed by numbers 1,2,3,4,5 (without repeating digitsi) = 5*4*3*2*! = 5! = 120. Now, in half them unit’s digit will be bigger than the ten’s digit and in half of them it will be smaller. How many 3 digit numbers can be formed with the digits 1 2 3 4 and 5 which are divisible by 5 and in which the digits are not repeated?How many 3-digit numbers can be formed from the digits 1,2,3,4 and 5 assuming that (i) repetition of the digits is allowed? (ii) repetition of the digits is not allowed? Total possible numbers =5×4×3=60. How many numbers are in a 4 digit number? 1 There are 4 numbers (any number from 0-9) in a 4-digit number and the starting number should be 1 or bigger than 1. 2 The thousands place in a 4-digit number cannot be 0. 3 The smallest 4 digit number is 1000 and the greatest 4 digit number is 9999. 4 There are 9000 four-digit numbers in all. More What is the value of a 3 digit number?The value, therefore, is 4 × 10 = 40. The third number 2 is at the hundreds place. So 2 is multiplied by 100 and its value is 2 × 100 = 200. Therefore the number is 200 + 40 + 3 = 243. Decomposing a 3-digit number: In a three-digit number, there are three place values used – hundred’s, ten’s, and units. How are three digit numbers formed in math?In the same way, we can define three digit numbers as those which have digits in three place values – Units, Tens and Hundreds. These are also formed by combining any three single digit numbers. Look at the simulation below to see how a 3-digit number is formed from the largest 2-digit number. Which is the smallest 3 digit number in the world? 100 is the smallest 3-digit number and 999 is the greatest 3 digit number. A 3-digit number cannot start with 0; 10 tens make 1 hundred which is the smallest 3 digit number and 10 hundred make a thousand which is the smallest 4 digit number.
 Given 5 flags of different colours, how many different signals can be generated if each signal requires use of 2 flags, one below the other?
Number of ways of finding a flag for place 1 = 5 Number of remaining flags = 4 Number of ways of finding a flag for place 2 to complete the signal = 4 ∴ By fundamental principle of counting, the number of signals generated = 991 Views A coin is tossed 3 times and the outcomes are recorded. How many possible outcomes are there?
Event 1: A coin is tossed and the outcomes recorded. Number of outcomes Event 2: The coin is tossed again and the outcomes recorded. Number of outcomes Event 3: The coin is tossed third time and the outcomes recorded. Number of outcomes ∴ By fundamental principle of counting, the total number of outcomes recorded = 548 Views How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is allowed. Number of digits available = 5 Number of places for the digits = 3. Number of ways in which place (x) can be filled = 5 m = 5 Number of ways in which place (y) can be filled = 5 (∵ Repetition is allowed) n = 5 Number of ways in which place (z) can be filled = 5 (∵ Repetition is allowed) p = 5 ∴ By fundamental principle of counting, the number of 3-digit numbers formed. = m x n x p = 5 x 5 x 5 = 125 458 Views How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is not allowed. Number of ways in which place (x) can be filled = 5 m = 5 Number of ways in which place (y) can be filled = 4 (∵ Repetition is not allowed) n = 4 Number of ways in which place (z) can be filled = 3 (∵ Repetition is not allowed) p = 3 ∴ By fundamental principle of counting, the total number of 3 digit numbers formed = m x n x p = 5 x 4 x 3 = 60. 526 Views How many 3-digit odd numbers can be formed from the digits 1,2,3,4,5,6 if:(a) the digits can be repeated (b) the digits cannot be repeated?(a) Number of digits available = 6 Number of places [(x), (y) and (z)] for them = 3 Repetition is allowed and the 3-digit numbers formed are odd Number of ways in which box (x) can be filled = 3 (by 1, 3 or 5 as the numbers formed are to be odd) Number of ways of filling box (y) = 6 (∴ Repetition is allowed) Number of ways of filling box (z) = 6 (∵ Repetition is allowed) ∴ Total number of 3-digit odd numbers formed = m x n x p = 3 x 6 x 6 = 108 (b) Number of ways of filling box (x) = 3 (only odd numbers are to be in this box ) Number of ways of filling box (y) = 5 (∵ Repetition is not allowed) Number of ways of filling box (z) = 4 (∵ Repetition is not allowed) ∴ Total number of 3-digit odd numbers formed = m x n x p = 3 x 5 x 4 = 60. 231 Views How many three digits numbers can be formed using the digits 1 2 3 4 5 if digits Cannot be repeated?There are 504 different 3-digit numbers which can be formed from numbers 1, 2, 3, 4, 5, 6, 7, 8, and 9 if no repetition is allowed.
How many 3 digits numbers can be formed from the digits 1 2 3 4 and 5 Assuming that a repetitions of digits are allowed B repetitions of digits are not allowed?so 60(ans.)
How many 3Solution : (i) When repetition of digits is allowed:
No. of ways of choosing firsy digits = 5 No. of ways of choosing second digit = 5 No. of ways of choosing third digit = 5 Therefore, total possible numbers `= 5 xx 5 xx 5 = 125` (ii) When repetition of digits is not allowed: No. How many 3But there are 4 different numbers. So the number of 3-number combinations are- (1,2,3),(1,2,4),(1,3,4),(2,3,4). Each can be arranged in 6 ways, so we get 24 ways totally.
|
