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CHƯƠNG-4-MẠCH-ĐIỆN-3-PHA
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CHƯƠNG 4 MẠCH ĐIỆN 3 PHA
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Chuong 3_Mach 3 pha
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2K views18 pages
Chuong 3 - Mach 3 Pha
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Ví dụ 1:
Cho mạch điện ba pha đối xứng như
Hình 2. Biết 𝐸𝐴\=200∠0𝑜[𝑉].
Tải 1 nối hình sao [Y] có: 𝑍1\=12+𝑗9[𝛺]
Tải 2 nối hình tam giác [∆] có:
𝑃2\=6[𝐾𝑊]; 𝑐𝑜𝑠𝜑2\=0,84 [𝞿𝟐\>𝟎].
- Tính 𝐼𝑑1, 𝐼𝑝1, 𝐼𝑑2, 𝐼𝑝2.
- Tính P, Q, S toàn mạch.
- Tính 𝐼𝑑 và cosφ toàn mạch
LỜI GIẢI
- Tính Id1, Ip1, Id2, Ip2.
❖ Xét tải 1 nối sao: 𝑼𝒅𝟏\=√𝟑.𝑼𝒑𝟏\=𝑼𝒅\=√𝟑.𝑬𝒑\=𝟐𝟎𝟎√𝟑[𝑽]
Id1\=Ip1 \=Up1
Z1\=Ep
Z1\=200
√[122+92]\=13,33[A]
❖ Xét tải 2 nối tam giác: 𝑼𝒅𝟐\=𝑼𝒑𝟐\=𝑼𝒅\=√𝟑.𝑬𝒑\=𝟐𝟎𝟎√𝟑[𝑽]
Id2\=P2
√3.Ud2.cosφ2\=6000
√3.200√3.0,84\=11,9[A]
\=>Ip2\=Id2
√3\=11,9
√3\=6,87[A]
𝐶𝑜𝑠𝜑2\=0,84\=>𝜑2\=32,860 [𝐷𝑜𝜑2\>0]
- Tính công suất của toàn mạch:
𝑃𝑡𝑚 \=𝑃1+𝑃2\=3𝑅1𝐼𝑝1
2+𝑃2\=3.13,332.12+6000\=12396,8[𝑊]
𝑄𝑡𝑚\=𝑄1+𝑄2\=3𝑋1𝐼𝑝1
2+𝑃2.𝑡𝑔𝜑2\=3.13,332.9+6000.𝑡𝑔[32,860]\=8673,23[𝑉𝐴𝑟]
𝑆𝑡𝑚\=√[𝑃𝑡𝑚
2+𝑄𝑡𝑚
2\=15129,62[𝑉𝐴]
- Tính Id và cosφ toàn mạch.
+ Tính dòng điện dây tổng: 𝑰𝒅\=𝑺𝒕𝒎
√𝟑.𝑼𝒅\=𝟏𝟓𝟏𝟐𝟗,𝟔𝟐
√𝟑.𝟐𝟎𝟎.√𝟑\=𝟐𝟓,𝟐𝟏[𝑨]
+ Hệ số công suất cosφ 𝒄𝒐𝒔𝝋𝒕𝒎\=𝑷𝒕𝒎
𝑺𝒕𝒎 \=𝟏𝟐𝟑𝟗𝟔,𝟖
𝟏𝟓𝟏𝟐𝟗,𝟔𝟑\=𝟎,𝟖𝟐
Z2
Z2
Z1Z1Z1
A1
B1
C1
A2
B2
C2
EB
.
Id
.Id2
.
Id1
.
Z2
EC
.
EA
.
Hình 2
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